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TRIANGLE ANGLES TEST-2

TYT-AYT Geometry issues, angles in triangle test-2 and their solutions …

iç açıortay dış açıortay soruları

Question 1-) ABC is a triangle, [BD] and [CD] bisector, if m (BDC) = 52 °; How many degrees is m (BAC) = x?

dış teğet çember soruları

Question 2-) ABC is a triangle, [BD] and [CD] bisector, if m (BDC) = 50 °; How many degrees is m (CAD) = x?

dış teğet çemberin merkezi soruları

Question 3-) In ABC triangle; D is the center of the outer tangent circle, if m (ADB) = x, m (BDC) = y, m (BAC) = 7x-5 °, m (ACB) = y-20 °; How many degrees is x?

üçgende açılar çözümlü sorular 9. sınıf

Question 4-) If KN parallel [CP, m (ACB) = m (BCP), | AC | = | BC |, m (CAK) = 60 °; How many degrees is m (NAB) = x?

üçgende açılar soru

Question 5-) If [AD parallel NP, [AC] bisector, | AB | = | CD |, m (ABN) = 2m (PBD); How many degrees is m (DCA) = x?

üçgenler çözümlü sorular

Question 6-) ABC is a triangle, | AB | = | AE | = | BD |, if m (EAC) = 24 °, m (CBD) = 30 °; How many degrees is m (ACB) = x?

açılar çözümlü sorular

Question 7-) ABC triangle, if | AP | = | PC |, | FA | = | FB | = | FP |, if m (ACB) = 33 °; How many degrees is m (BAF) = x?

açılar soruları

Question 😎 If | AB | = | BC | = | CD | = | DE |, if m (EDC) = m (CDB); How many degrees is m (DAE) = x?

TEST-2 SOLUTIONS FOR TRIANGLE ANGLES

bir dış açıortay bir iç açıortay

Solution: m (BDC) = 52 °, formed by the intersection of triangle ABC with an inner bisector and an outer bisector, will be half the angle m (BAC), so m (BAC) = 2.52 ° = 104 °.

dış teğet çember ile ilgili çözümlü sorular

Solution: Since the triangle ABC intersects an inner bisector and an outer bisector, m (BAC) = 100 °. If there is any two of the two outer bisectors in the triangle, the third is the bisector. (Point D is the center of the outer tangent circle of triangle ABC.) In this case, m (CAD is CAD. ) = x = 40 °.

iki dış açıortay ile bir iç açıortay

Solution: [AD], [BD], [CD] is bisector. ABC triangle; With the inner bisector of [BD], 2y = 7x-5 ° from the outer bisector of [CD], and 2x = y-20 ° from the outer bisector [AD] with the inner bisector of [BD].

üçgende açılar soru çözümü

Solution: Equilateral angles from inside angles are 30 degrees. In an isosceles triangle, m (BAC) = 75 °. From the right angle x = 45 °.

üçgende açılar soruları ve çözümleri

Solution: If we say m (BAC) = m (CAD) = a, then m (ABN) = 2a from inside angles. If m (ABN) = 2a then m (PBD) = a. M (ADB) = a (internal inverse angle). | AC | = | CD | Since | AB | = | AC | m (ACB) = 2a (outer angle). In the triangle ABC, m (ACB) = m (CBA) = 2a. Then 5a = 180 °, a = 36 °. x = 108 °.

üçgende açılar soruları ve cevapları

Solution: | AB | = | AE |; m (AEB) = m (EBA) = b + 30 °, | AB | = | BD |; m (ADB) = m (BAD) = a + 24 ° A + 2b = 120 ° in triangle ABE, 2a + b = 132 ° in triangle USA. From the solution of a system of equations with two unknowns, b = 36 °. x = 42 ° is calculated.

üçgende açılar çözümlü sorular

Solution: Since a + b = 66 ° (outer angle), 2x + 2 (a + b) = 180 ° in triangle ABP; 2x = 180 ° -132 °, x = 24 °.

matematik üçgenler test

Solution: From top to bottom, in the triangle, equilateral angle, outer angle, equilateral angle in triangle, equilateral angle in triangle, outer angle in triangle, equilateral angle are written. The interior angles of the triangle are added together and the angle x is calculated